is a “30 gram ball” some kind of archeaic unit? 30/5000 = 1/166 != 23/300 = 1/13.
but anyway, I feel this ruling would open an even better exploit the other way. Shoot an enlarged half-gram grain of sand weighing 30 gram at 300 meters per second, when it travels through the ring it will reduce down to it’s original size increasing speed to 19.2 km/s, having a new kenetic energy of 92 megajoules or 22kg of tnt.
In dnd terms that’s maybe 6d6 fire damage, range 10/30.
30 grams is a round number somewhere in the ballpark of a musket ball. I am also uncertain as to how you ended up with 19.2 km/s.
To the best of my recollection the energy should be conserved according to the formula: energy = mass * velocity squared
Mass is in kg and velocity is in m/s
So solving for v would give us around 2.3 km/s for a 0.5 g projectile. At that speed, the projectile would most likely detonate immedeately due to air resistance rendering it problematic as a firearm.
is a “30 gram ball” some kind of archeaic unit? 30/5000 = 1/166 != 23/300 = 1/13.
but anyway, I feel this ruling would open an even better exploit the other way. Shoot an enlarged half-gram grain of sand weighing 30 gram at 300 meters per second, when it travels through the ring it will reduce down to it’s original size increasing speed to 19.2 km/s, having a new kenetic energy of 92 megajoules or 22kg of tnt.
In dnd terms that’s maybe 6d6 fire damage, range 10/30.
30 grams is a round number somewhere in the ballpark of a musket ball. I am also uncertain as to how you ended up with 19.2 km/s.
To the best of my recollection the energy should be conserved according to the formula: energy = mass * velocity squared
Mass is in kg and velocity is in m/s
So solving for v would give us around 2.3 km/s for a 0.5 g projectile. At that speed, the projectile would most likely detonate immedeately due to air resistance rendering it problematic as a firearm.
13*13=169, so the kinetic energy would be almost the same (but not momentum).