• KISSmyOS@lemmy.world
    link
    fedilink
    arrow-up
    1
    arrow-down
    7
    ·
    edit-2
    1 year ago

    1D4 = 1D6 - 1 (minimum: 1)
    2D4 = 1D6 + 1
    3D4 = 2D6
    4D4 = 3D6

    Trust me, you won’t notice any practical difference.

    • Schmeckinger@feddit.de
      link
      fedilink
      arrow-up
      10
      ·
      edit-2
      1 year ago

      You can replace D4 with D6, but not like this. Just reroll all D6 that are 5 or 6. Your options give the advantage to D6 in the 1 and 4 option and to the D4 in the 2 and 3 option. No equal outcomes even if you factor in the average.

      Throw 1 D4 please. Ok I got 5.

      • KISSmyOS@lemmy.world
        link
        fedilink
        arrow-up
        1
        arrow-down
        3
        ·
        1 year ago

        The difference is purely mathematical. It won’t impact any balance in game at all.

          • KISSmyOS@lemmy.world
            link
            fedilink
            arrow-up
            1
            arrow-down
            4
            ·
            1 year ago

            If you took a system that uses D4, replaced that with D6 according to my table and didn’t tell your players that the system was actually meant to be played with D4, do you really think they’d notice any imbalance? Would it affect their fun?
            No, not at all. You only notice a difference if you calculate it, it won’t suddenly make your character class or weapon imbalanced.

            • nybble41@programming.dev
              link
              fedilink
              arrow-up
              6
              ·
              1 year ago

              The fact that you’ve made it impossible to roll an 8 by replacing 2d4 with 1d6+1 might impact the game just a bit. Also with 2d4 a 5 is 4x as likely (1+4, 2+3, 3+2, 4+1) as a 2 (1+1) or 8 (4+4); with 1d6+1 all outcomes from 2 to 7 are equally likely, so you’re far more likely to get a critical hit or critical miss (if the game has that sort of thing, and you adjust it for the reduced range).